417 lines
10 KiB
Text
417 lines
10 KiB
Text
{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"\n",
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"# Chapter 3: Conditionals & Exceptions"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Content Review"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"Read [Chapter 3](https://nbviewer.jupyter.org/github/webartifex/intro-to-python/blob/master/03_conditionals.ipynb) of the book. Then work through the eight review questions."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"### Essay Questions "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"Answer the following questions briefly with *at most* 300 characters per question!"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q1**: What is the **singleton** design pattern? How many objects does the expression `[True, False, True, False]` generate in memory?"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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" "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q2**: What do we mean when we talk about **truthy** and **falsy** expressions?"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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" "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q3**: Describe in your own words the concept of **short-circuiting**! What does it imply for an individual sub-expression in a boolean expression?"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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" "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q4**: Explain how the conceptual difference between a **statement** and an **expression** relates to the difference between a **conditional statement** and a **conditional expression**."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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" "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q5**: Why is the use of **temporary variables** encouraged in Python?"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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" "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q6**: What does the `finally`-clause enforce in this code snippet? How can a `try` statement be useful *without* an `except`-clause?"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"```python\n",
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"try:\n",
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" print(\"Make a request to a service on the internet\")\n",
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"finally:\n",
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" print(\"This could be clean-up code\")\n",
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"```"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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" "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"### True / False Questions"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"Motivate your answer with *one short* sentence!"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q7**: The objects `True`, `False`, and `None` represent the idea of *yes*, *no*, and *maybe* answers in a natural language.\n",
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"\n",
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"Hint: you also respond with a code cell."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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" "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q8**: The `try` statement is useful for handling **syntax** errors."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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" "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Coding Exercises"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"### Discounting Customer Orders"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q9.1**: Write a function `discounted_price()` that takes the positional arguments `unit_price` (of type `float`) and `quantity` (of type `int`) and implements a discount scheme for a line item in a customer order as follows:\n",
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"\n",
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"- if the unit price is over 100 dollars, grant 10% relative discount\n",
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"- if a customer orders more than 10 items, one in every five items is for free\n",
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"\n",
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"Only one of the two discounts is granted, whichever is better for the customer.\n",
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"\n",
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"The function should then return the overall price for the line item. Do not forget to round appropriately."
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"def discounted_price(...):\n",
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" ..."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q9.2**: Calculate the final price for the following line items of an order:\n",
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"- $7$ smartphones @ $99.00$ USD\n",
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"- $3$ workstations @ $999.00$ USD\n",
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"- $19$ GPUs @ $879.95$ USD\n",
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"- $14$ Raspberry Pis @ $35.00$ USD"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"discounted_price(...)"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"discounted_price(...)"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"discounted_price(...)"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"discounted_price(...)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q9.3**: Calculate the last two line items with order quantities of $20$ and $15$. What do you observe?"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"discounted_price(...)"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"discounted_price(...)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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" "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q9.4**: Looking at the `if`-`else`-logic in the function, why do you think the four example line items in **Q9.2** were chosen as they were?"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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" "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"### Fizz Buzz"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"The kids game [Fizz Buzz](https://en.wikipedia.org/wiki/Fizz_buzz) is said to be often used in job interviews for entry-level positions. However, opinions vary as to how good of a test it is (cf., [source](https://news.ycombinator.com/item?id=16446774)).\n",
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"\n",
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"In its simplest form, a group of people starts counting upwards in an alternating fashion. Whenever a number is divisible by $3$, the person must say \"Fizz\" instead of the number. The same holds for numbers divisible by $5$ when the person must say \"Buzz.\" If a number is divisible by both numbers, one must say \"FizzBuzz.\" Probably, this game would also make a good drinking game with the \"right\" beverages."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q10.1**: First, create a list `numbers` with the numbers from 1 through 100. You could type all numbers manually, but there is, of course, a smarter way. The built-in [range()](https://docs.python.org/3/library/functions.html#func-range) may be useful here. Read how it works in the documentation. To make the output of [range()](https://docs.python.org/3/library/functions.html#func-range) a `list` object, you have to wrap it with the [list()](https://docs.python.org/3/library/functions.html#func-list) built-in (i.e., `list(range(...))`)."
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"numbers = ..."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q10.2**: Loop over the `numbers` list and replace numbers for which one of the two (or both) conditions apply with text strings `\"Fizz\"`, `\"Buzz\"`, or `\"FizzBuzz\"` using the indexing operator `[]` and the assignment statement `=`.\n",
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"\n",
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"In [Chapter 1](https://nbviewer.jupyter.org/github/webartifex/intro-to-python/blob/master/01_elements.ipynb), we saw that Python starts indexing with `0` as the first element. Keep that in mind.\n",
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"\n",
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"So in each iteration of the `for`-loop, you have to determine an `index` variable as well as check the actual `number` for its divisors.\n",
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"\n",
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"Hint: the order of the conditions is important!"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"for number in numbers:\n",
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" ..."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**Q10.3**: Create a loop that prints out either the number or any of the Fizz Buzz substitutes. Do it in such a way that we do not end up with 100 lines of output here."
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"for number in numbers:\n",
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" print(...)"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.7.3"
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},
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"toc": {
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"base_numbering": 1,
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"nav_menu": {},
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"number_sections": false,
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"sideBar": true,
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"skip_h1_title": true,
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"title_cell": "Table of Contents",
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"title_sidebar": "Contents",
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"toc_cell": false,
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"toc_position": {},
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"toc_section_display": false,
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"toc_window_display": false
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}
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},
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"nbformat": 4,
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"nbformat_minor": 2
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}
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